When the current gets through the resistors, it will rejoin and go back through the battery. We don't yet know how much, but we might expect more might run through the small resistance ("follow the path of least resistance").
Some will run through one of the resistors, some through the other. When the current reaches the node joining the two resistors it must split. As the current $I$ runs around the circuit, as it passes through the wires, nothing happens to the potential (it doesn't change) by principle 4. In steady state (which takes about a nanosecond to establish in a circuit like this that would fit on a table). Once it's connected up into a loop, it can create a flow - an electric current. The battery maintains a potential difference across its terminals by principle 5 so it's like it's trying to push current out of its high end. To approach this problem, let's first get a sense of what's happening ("tell the story of the problem"). A battery is a device that maintains a fixed potential difference across its terminals.An element (e.g., a wire) having a 0 resistance is at a uniform potential: There is no potential drop since $R = 0$.Following around any loop in an electrical network the potential has to come back to the same value (sum of drops = sum of rises).The proportionality constant is the resistance: $ΔV = IR$. Across any single resistor, the potential drop across the resistor is proportional to the current through the resistor.The total amount of current flowing into any volume in an electrical network equals the amount flowing out.To answer the questions in the problem we have our five tools to bring to bear: Kirchhoff's principles, the 0-resistance-wire heuristic, and our definition of what a battery is. We've drawn the diagram in two forms: the semi-realistic one on the left and the more standard symbolic form on the right. Assume the battery and resistors are ideal and the connecting wires are resistanceless. If the battery maintains a voltage difference of $V_0$ across its terminals, find the current in and voltage drop across each resistor. Two resistors of resistance $R_1$ and $R_2$ are connected to each other and to a battery as shown in the diagram(s) at the right. Let's see how this works by solving a problem to determine the potential drops and currents in a pair of parallel resistors. Two circuit elements are in parallel means that they are connected so that whatever the potential is at the top of one of them is also the potential at the top of the other similarly, the bottoms of the two elements are also at the same potential. In this examples, we'll consider the simplest example of a parallel circuit: one battery and two resistors connected in parallel.
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